Question

For the differential equation, find the general solution:

(e^x + e^–x) dy – (e^x – e–x) dx = 0

Answer 1

(e^x + e^-x) dy = (e^x - e^-x) dx = 0

⇒ `dy = ((e^x - e^(-x))/(e^x + e^(-x))) dx`

On integrating

`int 1. dy = int ((e^x - e^(-x))/(e^x + e^(-x))) dx`

y = log (e^x + e^-x) + C