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рдкреНрд░рд╢реНрди
For f(x) = x + `1/x` (x ≠ 0)
рдкрд░реНрдпрд╛рдп
local maximum value is 2
local minimum value is –2
local maximum value is –2
local minimum value < local maximum value
MCQ
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рдЙрддреНрддрд░
local maximum value is –2
Explanation:
f'(x) = 1 – `1/x^2`
f'(x) = 0
1 = `1/x^2`
⇒ x2 = 1
⇒ x = ±1
At x = 1, f(1) = 2 (Local minimum for x > 0)
At x = –1, f(–1) = –2 (Local maximum for x < 0).
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