Question

For a uniformly charged thin spherical shell, what is the electric field at any point inside the shell (r < R)?

पर्याय

• \[E = \frac{1}{4\pi\varepsilon_0} \cdot \frac{Q}{R^2}\]

• \[E = \frac{Q}{4\pi\varepsilon_0 R}\]

• \[E = \frac{Q}{4\pi\varepsilon_0 r^2}\]

• E = 0

Answer 1

Inside a uniformly charged spherical shell, the electric field is zero everywhere. This is a fundamental result derived from Gauss's Law: when a concentric Gaussian surface is drawn inside the shell (r < R), it encloses zero charge, so the flux through it is zero and therefore E = 0. This is a key property of spherical shells.