Question

For a uniformly charged thin spherical shell of radius R with total charge Q, the electric field outside the shell (r > R) is:

पर्याय

• \[E = \frac{\sigma}{2\varepsilon_0}\]

• \[E = \frac{1}{4\pi\varepsilon_0} \cdot \frac{Q}{r^2}\]

• \[E = \frac{Q}{\varepsilon_0 r}\]

• \[E = \frac{Q}{2\pi\varepsilon_0 r^2}\]

Answer 1

For a uniformly charged spherical shell of radius R with total charge Q, at any point outside the shell (r > R), the electric field is the same as that of a point charge Q located at the center. Using Gauss's Law with a concentric spherical surface, E = (1/4πε₀) × (Q/r²). This demonstrates the shell theorem.