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प्रश्न
Find ‘x’, if:
बेरीज
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उत्तर
sin 60° = `"Perpendicular"/"Hypotenuse"`
sin 60° = `(20)/x`
`sqrt(3)/(2) = (20)/x`
x = `(40)/sqrt(3)`
x = `40/1.732 ...sqrt3 = 1.732`
x = 23.1
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Solution of Right Triangles
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