Advertisements
Advertisements
प्रश्न
Find x, if : log7 (2x2 - 1) = 2
बेरीज
Advertisements
उत्तर
Consider the equation
log7( 2x2 - 1 ) = 2
⇒ 72 = 2x2 - 1
⇒ 7 x 7 = 2x2 - 1
⇒ 2x2 - 1 - 49 = 0
⇒ 2x2 - 50 = 0
⇒ 2x2 = 50
⇒ x2 = `50/2`
⇒ x2 = 25
⇒ x = `+-sqrt25`
⇒ x = 5 .....[ neglecting the negative value ]
shaalaa.com
Interchanging Logarithmic and Exponential Forms
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Express the following in logarithmic form:
`3^-2 = 1/9`
Solve for x : log10 x = -2.
Find the logarithm of : 0.125 to the base 2
State, true or false : If log10 x = a, then 10x = a.
State, true or false : log2 8 = 3 and log8 = 2 = `1/3`
Find x, if : logx 2 = - 1.
Find x, if : log432 = x - 4
Evaluate : log2 ( 1 ÷ 8 )
Given log2 x = m. Express 2m - 3 in terms of x.
Solve for x:
log(x - 1) + log (x + 1) = log21
