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प्रश्न
Find x, if \[\left( \frac{1}{4} \right)^{- 4} \times \left( \frac{1}{4} \right)^{- 8} = \left( \frac{1}{4} \right)^{- 4x}\]
बेरीज
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उत्तर
We have:
\[\left( \frac{1}{4} \right)^{- 4} \times \left( \frac{1}{4} \right)^{- 8} = \left( \frac{1}{4} \right)^{- 4x}\]
`(1/4)^(-12)=(1/4)^(-4x)`
\[( a^m \times a^n = a^{m + n} )\]
-12 = -4x
3 = x
x = 3
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