Question

Find x, if \[\left( \frac{1}{4} \right)^{- 4} \times \left( \frac{1}{4} \right)^{- 8} = \left( \frac{1}{4} \right)^{- 4x}\]

 

Answer 1

We have:

\[\left( \frac{1}{4} \right)^{- 4} \times \left( \frac{1}{4} \right)^{- 8} = \left( \frac{1}{4} \right)^{- 4x}\]

`(1/4)^(-12)=(1/4)^(-4x)`

\[( a^m \times a^n = a^{m + n} )\]

-12 = -4x

3 = x

x = 3