Advertisements
Advertisements
प्रश्न
Find x.
`(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`
Advertisements
उत्तर
We have, `(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`
Using law of exponents,
am × an = (a)m + n ...[∵ a is non-zero integer]
Then, `(2/5)^(2x + 6 + 3) = (2/5)^(x + 2)`
On comparing powers of `(2/5)`, we get
2x + 6 + 3 = x + 2
⇒ 2x + 9 = x + 2
⇒ x = –7
APPEARS IN
संबंधित प्रश्न
The value of `1/4^-2` is ______.
For a non-zero rational number z, (z–2)3 is equal to ______.
Which of the following is not the reciprocal of `(2/3)^4`?
The value of [2–1 × 3–1]–1 is ______.
(–7)–4 × (–7)2 = (–7)–2
By what number should we multiply (–29)0 so that the product becomes (+29)0.
`(16 xx 10^2 xx 64)/(2^4 xx 4^2)`
Fill in the blanks
If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.
Find x.
5x + 5x – 1 = 750
