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Find the Vector Equations of the Coordinate Planes. - Mathematics

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प्रश्न

Find the vector equations of the coordinate planes.

 
बेरीज
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उत्तर

\[ \text{ Vector equation of XY-plane}\]

\[\text{ This plane is passing through the origin whose position vector is } \vec{a} = 0^\to \text{ and perpendicular to  z-axis whose position vector is } \hat{k} .\]

\[\text{ So, the equation of the XY-plane is } \]

\[ \vec{r} . \vec{n} = \vec{a} . \vec{n} \]

\[ \Rightarrow \vec{r} . \hat{k}  = \vec{0} . \hat{k} \]

\[ \Rightarrow \vec{r} . \hat{k} = 0\]

\[\text{ Vector equation of YZ-plane } \]

\[\text{ This plane is passing through the origin whose position vector is } a^\to = 0^\to \text{ and perpendicular tox-axis whose position vector is } \hat{i} .\]

\[\text{ So, the equation of the YZ-plane is } \]

\[ \vec{r} . \vec{n} = \vec{a} . \vec{n} \]

\[ \Rightarrow \vec{r} . \hat{i}  = \vec{0} . \hat{i}  \]

\[ \Rightarrow \vec{r} . \hat{i}  = 0\]

\[\text{ Vector equation of XZ-plane } \]

\[ \text{ This plane is passing through the origin whose position vector is } \vec{a} = \vec{0} \text{ and perpendicular toy-axis whose position vector is }  \hat{j} .\]

\[\text{ So, the equation of the XZ-plane is } \]

\[ \vec{r} . \vec{n} = \vec{a} . \vec{n} \]

\[ \Rightarrow \vec{r} . \hat{j}  = \vec{0} . \hat{j}  \]

\[ \Rightarrow \vec{r} . \hat{j}  = 0\]

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पाठ 29: The Plane - Exercise 29.03 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 29 The Plane
Exercise 29.03 | Q 3 | पृष्ठ १३

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