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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find variance and S.D. for the following set of numbers: 65, 77, 81, 98, 100, 80, 129

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प्रश्न

Find variance and S.D. for the following set of numbers:

65, 77, 81, 98, 100, 80, 129

बेरीज
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उत्तर १

We construct the following table to compute variance and S.D.:

xi `x_"i" - bar(x)` `(x_"i" - bar(x))^2`
65 – 25 625
77 – 13 169
81 – 9 81
98 8 64
100 10 100
80 – 10 100
129 39 1521
`sumx_"i"` = 630   `sum(x_"i" - barx)^2` = 2660

From the table, `sumx_"i"` = 630, n = 7

∴ `barx = (sumx_"i")/"n" = 630/7` = 90

Var (X) = `(sum(x_"i" - barx)^2)/"n" = 2660/7` = 380

∴ S.D. = `sqrt("Var(X)")`

= `sqrt(380)`

= 19.49

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उत्तर २

xi

ui = xi – A
A = 98

ui2
65 – 33 1089
77 – 21 441
81 – 17 289
98 0 0
100 2 4
80 – 18 324
129 31 961
  `sumu_"i"` = – 56 `sumu_"i"^2` = 3108

From the table, `sumu_"i"` = – 56, `sumu_"i"^2` = 3108, n = 7

∴ Var(x) = Var(u) = `(sumu_"i"^2)/"n" - ((sumu_"i")/"n")^2`

= `3108/7 - ((-56)/7)^2`

= 444 – 64

= 380

S.D.(x) = `sqrt("Var(x)")`

= `sqrt(380)`

= 19.49

Hence, variance = 380, S.D. = 19.49

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Standard Deviation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Measures of Dispersion - Exercise 8.2 [पृष्ठ १८४]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 8 Measures of Dispersion
Exercise 8.2 | Q 2 | पृष्ठ १८४

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