Advertisements
Advertisements
प्रश्न
Find the value of the unknown in the following proportion :
`1/2 : "m" :: 14/9 : 4/3`
Advertisements
उत्तर
`1/2 : "m" :: 14/9 : 4/3`
`1/2 : "m" :: 14/9 : 4/3`
⇒ `"m" xx 14/9 = 1/2 xx 4/3`
⇒ `"m" = 1/2 xx 4/3 xx 9/14 = 3/7`
m = `3/7`
APPEARS IN
संबंधित प्रश्न
If y is the mean proportional between x and z; show that xy + yz is the mean proportional between x2 + y2 and y2 + z2.
If `x/a = y/b = z/c` prove that `(2x^3 - 3y^3 + 4z^3)/(2a^3 - 3b^3 + 4c^3) = ((2x - 3y + 4z)/(2a - 3b + 4c))^3`
Determine if the following ratio form a proportion:
25 cm : 1 m and Rs 40 : Rs 160
If 25 : 35 : : 45 : x, then the value of x is
What number must be added to each of the numbers 15, 17, 34 and 38 to make them proportional?
If q is the mean proportional between p and r, prove that: p3 – 3q2 + r2 = `q^4(1/p^2 - 3/q^2 + 1/r^2)`
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
2 kg : 80 kg and 25 g : 625 g
Are the following statements true?
45 km : 60 km = 12 hours : 15 hours
What number must be added to each of the numbers 4, 6, 8, 11 in order to get the four numbers in proportion?
If x, y and z are in continued proportion, Prove that:
`x/(y^2.z^2) + y/(z^2.x^2) + z/(x^2.y^2) = 1/x^3 + 1/y^3 + 1/z^3`
