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प्रश्न
Find the value of \[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right)\]
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उत्तर
\[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right) = 2 \sec^{- 1} \left( \sec\frac{\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{\pi}{6} \right)\]
\[ = 2 \times \frac{\pi}{3} + \frac{\pi}{6}\]
\[ = \frac{5\pi}{6}\]
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