Advertisements
Advertisements
प्रश्न
Find two consecutive positive odd numbers, the sum of whose squares is 74.
Advertisements
उत्तर
Let the consecutive positive odd numbers be x and x + 2.
From the given information,
x2 + (x + 2)2 = 74
2x2 + 4x + 4 = 74
2x2 + 4x – 70 = 0
x2 + 2x – 35 = 0
(x + 7)(x – 5) = 0
x = –7, 5
Since, the numbers are positive, so, x = 5.
Thus, the numbers are 5 and 7.
संबंधित प्रश्न
The sum of the squares of two positive integers is 208. If the square of the large number is 18 times the smaller. Find the numbers.
Find the two natural numbers which differ by 5 and the sum of whose squares is 97.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
Divide 20 into two parts such that three times the square of one part exceeds the other part by 10.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
The sum of two natural numbers is 5 and the sum of their reciprocals is `5/6`, the numbers are ______.
The product of two consecutive even whole numbers is 24, the numbers are ______.
Two integers differ by 2 and sum of their squares is 52. The integers are ______.
In a school, a class has 40 students out of which x are girls. If the product of the number of girls and number of boys in the class is 375; the number of boys in the class is ______.
The difference between the digits of a two-digit number is 2 and the product of digits is 24. If tens digit is bigger, the number is ______.
