Advertisements
Advertisements
प्रश्न
Divide 20 into two parts such that three times the square of one part exceeds the other part by 10.
Advertisements
उत्तर
Let the two parts be x and y.
From the given information,
= x + y = 20 ⇒ y = 20 – x
= 3x2 = (20 – x) + 10
= 3x2 = 30 – x
= 3x2 + x – 30 = 0
= 3x2 – 9x + 10x – 30 = 0
= x(3x + 10) – 3(3x + 10) = 0
= (3x + 10)(x – 3) = 0
= `x = 3, x = (-10)/3`
Since, x cannot be equal to `(-10)/3`, so, x = 3.
Thus, one part is 3 and the other part is 20 – 3 = 17.
संबंधित प्रश्न
The sum of the squares of two positive integers is 208. If the square of the large number is 18 times the smaller. Find the numbers.
The product of two consecutive integers is 56. Find the integers.
The sum of the squares of two consecutive natural numbers is 41. Find the numbers.
The sum of a number and its reciprocal is 4.25. Find the number.
Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocals is `7/10`.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
In a school, a class has 40 students out of which x are girls. If the product of the number of girls and number of boys in the class is 375; the number of boys in the class is ______.
The difference between the digits of a two-digit number is 2 and the product of digits is 24. If tens digit is bigger, the number is ______.
If 18 is added to a two-digit number, its digits are reversed. If the product of the digits of the number is 24, the number is ______.
