मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Find the values of sin(480°)

Advertisements
Advertisements

प्रश्न

Find the values of sin(480°)

बेरीज
Advertisements

उत्तर

sin(480°) = sin(360° + 120°)

= sin 120°

= sin(90° + 30°)

= cos 30°

= `sqrt(3)/2`

shaalaa.com
Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.3 [पृष्ठ १०४]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.3 | Q 1. (i) | पृष्ठ १०४

संबंधित प्रश्‍न

Find the values of cos(300°)


`(5/7, (2sqrt(6))/7)` is a point on the terminal side of an angle θ in standard position. Determine the six trigonometric function values of angle θ


If sin x = `15/17` and cos y = `12/13, 0 < x < pi/2, 0 < y < pi/2`, find the value of tan(x + y)


If sin A = `3/5` and cos B = `9/41 0 < "A" < pi/2, 0 < "B" < pi/2`, find the value of sin(A + B)


Find cos(x − y), given that cos x = `- 4/5` with `pi < x < (3pi)/2`  and sin y = `- 24/25` with `pi < y < (3pi)/2`


Find the value of cos 105°.


Prove that sin(π + θ) = − sin θ.


Prove that sin(30° + θ) + cos(60° + θ) = cos θ


Show that tan 75° + cot 75° = 4


Prove that sin(n + 1) θ sin(n – 1) θ + cos(n + 1) θ cos(n – 1)θ = cos 2θ, n ∈ Z


If cos(α – β) + cos(β – γ) + cos(γ – α) = `- 3/2`, then prove that cos α + cos β + cos γ = sin α + sin β + sin γ = 0


Prove that cot(A + B) = `(cot "A" cot "B" - 1)/(cot "A" + cot "B")`


Prove that `tan(pi/4 + theta) tan((3pi)/4 + theta)` = – 1


Prove that `tan (pi/4 + theta) - tan(pi/4 - theta)` = 2 tan 2θ


Express the following as a sum or difference
sin 4x cos 2x


Show that `((cos theta -cos 3theta)(sin 8theta + sin 2theta))/((sin 5theta - sin theta) (cos 4theta - cos 6theta))` = 1


Prove that cos(30° – A) cos(30° + A) + cos(45° – A) cos(45° + A) = `cos 2"A" + 1/4`


Show that cot(A + 15°) – tan(A – 15°) = `(4cos2"A")/(1 + 2 sin2"A")`


Choose the correct alternative:
`(sin("A" - "B"))/(cos"A" cos"B") + (sin("B" - "C"))/(cos"B" cos"C") + (sin("C" - "A"))/(cos"C" cos"A")` is 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×