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प्रश्न
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 6x + 1 = 0
बेरीज
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उत्तर
Given:
kx2 + 6x + 1 = 0
D = 62 − 4 × k × 1
= 36 − 4k
The given equation has real and distinct roots if D > 0.
∴ 36 − 4k > 0
⇒ 4k < 36
⇒ k < 9
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