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Find the values of k for which the given quadratic equation has real and distinct roots: kx2 + 6x + 1 = 0 - Mathematics

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प्रश्न

Find the values of k for which the given quadratic equation has real and distinct roots:

kx2 + 6x + 1 = 0

योग
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उत्तर

Given:

kx2 + 6x + 1 = 0

D = 62 − 4 × k × 1

= 36 − 4k 

The given equation has real and distinct roots if D > 0. 

∴ 36 − 4k > 0

⇒ 4k < 36

⇒ k < 9

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अध्याय 5: Quadratic equations - Exercise 5D [पृष्ठ ७८]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic equations
Exercise 5D | Q 7. (iii) | पृष्ठ ७८
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