So the correct value is x = 80°, and the reasoning in your screenshot (using ∠BAC and arc BC) is based on misreading which chords form the 40° angle.
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प्रश्न
Find the value of x in the following figure, where O is the centre of the circle:

बेरीज
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उत्तर
In the diagram, the 40° angle at A is between AB and AD, not between AB and AC. So it is ∠BAD, not ∠BAC.
Therefore, ∠BAD = 40° subtends arc BD, not arc BC.
So,
arc BD = 2 × 40° = 80°.
The 120° angle at P is formed by the intersection of chords AD and BC. For two chords intersecting inside a circle,
angle between them is `1/2` (sum of the intercepted arcs).
∠APC intercepts arcs AC and BD, so
120° = `1/2`(arc AC + arc BD)
240° = arc AC + 80°
arc AC = 160°.
Angle x at D is ∠ADC, an inscribed angle subtending arc AC:
x = `1/2` (arc AC) = `1/2` × 160° = 80°.
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Circles - Exercise 15A [पृष्ठ ३२९]
