मराठी

Find the value of x in the following figure, where O is the centre of the circle: 40°, 120° - Mathematics

Advertisements
Advertisements

प्रश्न

Find the value of x in the following figure, where O is the centre of the circle:

बेरीज
Advertisements

उत्तर

In the diagram, the 40° angle at A is between AB and AD, not between AB and AC. So it is ∠BAD, not ∠BAC.

Therefore, ∠BAD = 40° subtends arc BD, not arc BC.

So,

arc BD = 2 × 40° = 80°.

The 120° angle at P is formed by the intersection of chords AD and BC. For two chords intersecting inside a circle,

angle between them is `1/2` (sum of the intercepted arcs).

∠APC intercepts arcs AC and BD, so

120° = `1/2`(arc AC + arc BD)

240° = arc AC + 80°

arc AC = 160°.

Angle x at D is ∠ADC, an inscribed angle subtending arc AC:

x = `1/2` (arc AC) = `1/2` × 160° = 80°.

So the correct value is x = 80°, and the reasoning in your screenshot (using ∠BAC and arc BC) is based on misreading which chords form the 40° angle.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Circles - Exercise 15A [पृष्ठ ३२९]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 15 Circles
Exercise 15A | Q 1. (viii) | पृष्ठ ३२९
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×