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प्रश्न
Find the value of x in the following figure, where O is the centre of the circle:

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उत्तर
Step 1: Identify what the given 22° angle represents
The given angle is at point A, between chords
A–B (a diameter), and
A–C.
∠BAC = 22°
By the Inscribed Angle Theorem, an inscribed angle equals half the measure of the arc it intercepts:
∠BAC = `1/2` BC
`hat(BC)` = 2 × 22° = 44°
Step 2: Determine the arc intercepted by angle x at D
Angle x = ∠ADC is an inscribed angle that intercepts arc AC, but crucially:
It must be the arc not containing D.
D is on the upper part of the circle.
So the intercepted arc AC is the lower arc, which passes through B.
Arc AB = 180° (since AB is a diameter).
Arc BC = 44° (found above).
`hat(AC)` = 180° + 44° = 224°
Step 3: Use the Inscribed Angle Theorem
∠ADC = `1/2` AC
x = `1/2` × 224°
x = 112°
