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Find the value of tan-1(-13)+cot-1(13)+tan-1(sin(-π2)) - Mathematics

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प्रश्न

Find the value of `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`

बेरीज
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उत्तर

We have `tan^-1 (- 1/sqrt(3)) + cot^-1(1/sqrt(3)) + tan^-1(sin((-pi)/2))`

= `tan^-1(tan(- pi/6)) + cot^-1(cot  pi/3) + tan^-1(-1)`

= `- pi/6 + pi/3 + (- pi/4)`

= `-pi/12`

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पाठ 2: Inverse Trigonometric Functions - Exercise [पृष्ठ ३५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Exercise | Q 4 | पृष्ठ ३५

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