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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the value of 20C16 – 19C16 - Mathematics and Statistics

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प्रश्न

Find the value of 20C1619C16 

बेरीज
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उत्तर

20C1619C16 

= 19C16 + 19C1519C16  ...[∵ nCr + nCr–1 = n+1Cr]

= 19C15

= `(19!)/(15!(19 - 15)!)`

= `(19!)/(15!4!)`

= `(19 xx 18 xx 17 xx 16 xx 15!)/(15! xx 4 xx 3 xx 2 xx 1)`

= 19 × 6 × 17 × 2

= 3876

∴ 20C1619C16 = 19C15 = 3876

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पाठ 3: Permutations and Combination - Exercise 3.6 [पृष्ठ ६४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 3 Permutations and Combination
Exercise 3.6 | Q 1. (d) | पृष्ठ ६४

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