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How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated? - Mathematics

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प्रश्न

How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated?

बेरीज
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उत्तर

Those numbers divisible by 10 are those in which 0 is placed in the ones place.

Therefore, 0 is fixed at the units place.

Therefore, there will be as many ways as there are ways of filling 5 vacant places  

in succession by the remaining 5 digits (i.e., 1, 3, 5, 7 and 9).

The 5 vacant places can be filled in 5! ways.

Hence, required number of 6-digit numbers = 5! = 120

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पाठ 7: Permutations and Combinations - Miscellaneous Exercise [पृष्ठ १५७]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 7 Permutations and Combinations
Miscellaneous Exercise | Q 5 | पृष्ठ १५७

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