Find the slope of the line y – x + 3 = 0.

बेरीज

Equation of given line is y – x + 3 = 0
i.e. y = x – 3
Comparing with y = mx + c, we get
m = Slope =1.

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पाठ 5: Locus and Straight Line - Miscellaneous Exercise 5 [पृष्ठ ७९]

पाठ 5 Locus and Straight Line
Miscellaneous Exercise 5 | Q 7 | पृष्ठ ७९

Find the slope of the following lines which pass through the point: (2, – 1), (4, 3)

Find the slope of the following lines which pass through the point: (– 2, 3), (5, 7)

Find the slope of the following lines which pass through the point: (2, 3), (2, – 1)

A line makes intercepts 3 and 3 on coordinate axes. Find the inclination of the line.

Without using Pythagoras theorem, show that points A (4, 4), B (3, 5) and C (– 1, – 1) are the vertices of a right-angled triangle.

Find the slope of the line passing through the following point: (1, 2), (3, – 5)

Find the slope of the line passing through the following point: (1, 3), (5, 2)

Find the slope of the line passing through the following point: (2, – 5), (3, – 1)

Find the slope of the line which makes an angle of 120° with the positive X-axis.

Find the slope of the line which makes intercepts 3 and – 4 on the axes.

Does point A(2, 3) lie on the line 3x + 2y – 6 = 0? Give reason.

Obtain the equation of the line containing the point: (2, 5) and perpendicular to the X−axis.

Find the equation of the line: containing the point T(7, 3) and having inclination 90°.

Find the equation of the line: containing the origin and having inclination 90°.