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प्रश्न
Find the principal value of the following:
`cot^(-1) (sqrt(3))`
बेरीज
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उत्तर
Let `cot^(-1) (sqrt(3)) = y`.
Then, `cot y = sqrt(3) = cot (pi/6)`.
We know that the range of the principal value branch of cot−1 is (0, π) and `cot (pi/6) = sqrt(3)`.
Where `pi/6 ∈ (0, pi)`
Therefore, the principal value of `cot^(-1) (sqrt(3))` is `pi/6`.
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