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प्रश्न
Find the principal value of the following:
`cos^(-1) (-1/2)`
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उत्तर
Let `cos^(-1) (-1/2)` = y
⇒ cos y = `-1/2 = -cos pi/3 = cos (pi - pi/3)`
We know that the range of the principal value branch of cos−1 is [0, π] and `cos((2pi)/3) = 1/2`.
Therefore, the principal value of `cos^(-1) (-1/2)` is `(2pi)/3`.
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