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प्रश्न
Find the polar coordinates of points whose cartesian coordinates are:
`(1, sqrt(3))`
बेरीज
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उत्तर
`r = sqrt(x^2 + y^2)`
`theta = tan^-1 (y/x)`
Point: (x, y) = `(1, sqrt3)`
`r = sqrt(1^2 + (sqrt3)^2) = sqrt(1+3) = sqrt4 = 2`
`theta = tan^-1 (sqrt3/1) = tan^-1 (sqrt3)`
`theta = pi/3` since the point lies in 1st quadrant
The polar coordinates are:
`(r, theta) = (2, pi/3)`
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Polar Co-ordinate System
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पाठ 2: Trigonometry - 1 - EXERCISE 2.2 [पृष्ठ ३१]
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