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Find the non-parametric form of vector equation and Cartesian equation of the plane passing through the point (2, 3, 6) and parallel to thestraight lines x-12=y+13=x-31 and x+32=y-3-5=z+1-3

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प्रश्न

Find the non-parametric form of vector equation and Cartesian equation of the plane passing through the point (2, 3, 6) and parallel to thestraight lines `(x - 1)/2 = (y + 1)/3 = (x - 3)/1` and `(x + 3)/2 = (y - 3)/(-5) = (z + 1)/(-3)`

बेरीज
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उत्तर

`vec"a" = 2hat"i" + 3hat"j" + 6hat"k"`

`vec"b" = 2hat"i" + 3hat"j" + hat"k"`

`vec"c" = 2hat"i" - 5hat"j" - 3hat"k"`

Non-parametric form of vector equation

`(vec"r" - vec"a")*(vec"b" xx vec"c")` = 0

`vec"b" xx vec"c" = |(hat"i", hat"j", hat"k"),(2, 3, 1),(2, -5, -3)|`

= `hat"i"(- 9 + 5) -hat"j"(- 6 - 2) + hat"k"(- 10 - 6)`

= `- 4hat"i" + 8hat"j" - 16hat"k"`

= `-4(hat"i" - 2hat"j" + 4hat"k")`

`[vec"r" - (2hat"i" + 3hat"j" + 6hat"k")]*[hat"i" + 2hat"j" + 4hat"k"]` = 0

`vec"r"*(hat"i" - 2hat"j" + 4hat"k") = 2 - 6 + 24`

`vec"r"*(hat"i" - 2hat"j" + 4hat"k")` = 20

Cartesian equation

`(xhat"i" + yhat"j" + zhat"k")*(hat"i" - 2hat"j" + 4hat"k")` = 20

`x - 2y + 4z - 20` = 0

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पाठ 6: Applications of Vector Algebra - Exercise 6.7 [पृष्ठ २६३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 6 Applications of Vector Algebra
Exercise 6.7 | Q 1 | पृष्ठ २६३

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