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प्रश्न
Find the kinetic energy of 4000 cc of a gas at S.T.P.
[Given: Standard pressure is 1.013 × 105 N/m2]
संख्यात्मक
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उत्तर
Data: V = 4000 cc = 4000 × 10−6 m3, P = 1.013 × 105 N/m2
Kinetic energy = `3/2 PV`
= `(3 xx 1.013 xx 10^5 xx 4000 xx 10^-6)/2`
= 3 × 1.013 × 2 × 102
= 6 × 1.013 × 102
= 6.078 × 102 J
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