Question

Find the kinetic energy of 4000 cc of a gas at S.T.P.

[Given: Standard pressure is 1.013 × 10⁵ N/m²]

Answer 1

Data: V = 4000 cc = 4000 × 10⁻⁶ m³, P = 1.013 × 10⁵ N/m²

Kinetic energy = `3/2 PV`

= `(3 xx 1.013 xx 10^5 xx 4000 xx 10^-6)/2`

= 3 × 1.013 × 2 × 10²

= 6 × 1.013 × 10²

= 6.078 × 10² J