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प्रश्न
Find the G.C.D for the following:
25ab3c, 100a2bc, 125ab
बेरीज
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उत्तर
25ab3c = 5 × 5 × a × b3 × c
100a2bc = 2 × 2 × 5 × 5 × a2 × b × c
125ab = 5 × 5 × 5 × a × b
G.C.D = 5 × 5 × a × b
= 25ab
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पाठ 3: Algebra - Exercise 3.9 [पृष्ठ ११५]
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