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Find the direction cosines of the normal to the plane 12x + 3y – 4z = 65. Also find the non-parametric form of vector equation of a plane and the length of the perpendicular to the plane from the

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प्रश्न

Find the direction cosines of the normal to the plane 12x + 3y – 4z = 65. Also find the non-parametric form of vector equation of a plane and the length of the perpendicular to the plane from the origin

बेरीज
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उत्तर

`vec"d" = 12hat"i" + 3hat"j" - 4hat"k"`

p = 65

`hat"d" = vec"d"/|vec"d"|`

= `(12hat"i" + 3hat"j" - 4hat"k")/sqrt(144 + 9 + 16)`

= `(12hat"i" + 3hat"j" - 4hat"k")/13`

`vec"r"*hat"d"` = p

`vec"r"* ((12hat"i" + 3hat"j" - 4hat"k")/13)`

= `(65/13)`

= 5

Direction cosines of `vec"d"` are `(12/13, 3/13, (-4)/13)` and Length of the ⊥r from the origin = 5 units.

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Different Forms of Equation of a Plane
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Applications of Vector Algebra - Exercise 6.6 [पृष्ठ २५९]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 6 Applications of Vector Algebra
Exercise 6.6 | Q 2 | पृष्ठ २५९

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