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Find the derivatives of the following: tan-1(cosx+sinxcosx-sinx)

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प्रश्न

Find the derivatives of the following:

`tan^-1 ((cos x + sin x)/(cos x - sin x))`

बेरीज
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उत्तर

Let y = `tan^-1 ((cos x + sin x)/(cos x - sin x))`

y = `tan^-1 ((cos x(1 + (sinx)/(cosx)))/(cos x(1 - (sin x)/(cos x))))`

y =  `tan^-1 ((1 + tanx)/(1 - tanx))`

= `tan^-1 ((tan  pi/4 + tan x)/(1 - tan  pi/4 * tan x))`

= `tan^-1 (tan (pi/4 + x))`

y = `pi/4 + x`

`("d"y)/("d"x)` = 0 + 1

`("d"y)/("d"x)` = 1

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.4 [पृष्ठ १७६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.4 | Q 18 | पृष्ठ १७६

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