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Find the derivatives of the following functions with respect to corresponding independent variables: y = cosec x . cot x

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प्रश्न

Find the derivatives of the following functions with respect to corresponding independent variables:

y = cosec x . cot x

बेरीज
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उत्तर

y = u v

⇒ y’ = uv’ + vu’

u = cosec x

⇒ u’ = – cosec x cot x

v = cot x

⇒ v’ = – cosec2 x

`("d"y)/("d"x)` = (cosec x)(– cosec2x) + cot x(– coseç x cot x)

= cosec3x – cosec x cot2x

= – cosec x (cosec2x + cot2x)

= `- 1/sinx (1/(sin^2x)+ (cos^2x)/(sin^2x))`

= `- ((1 + cos^2x))/(sinx sin^2x)`

= `- ((1 + cos^2x))/(sin^x)`

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Differentiation Rules
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [पृष्ठ १६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 14 | पृष्ठ १६०

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