मराठी

Find the derivative of the following w. r. t. x. : xexx+ex - Mathematics and Statistics

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प्रश्न

Find the derivative of the following w. r. t. x. : `(xe^x)/(x+e^x)`

बेरीज
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उत्तर

Let y = `(x"e"^x)/(x + "e"^x)`

Differentiating w.r.t. x, we get

`dy/dx = d/dx((x"e"^x)/(x + "e"^x))`

= `((x + "e"^x)d/dx(x"e"^x) -(x"e"^x)d/dx(x + "e"^x))/(x + "e"^x)^2`

=`((x + "e"^x)[xd/dx("e"^x) + "e"^xd/dx(x)] - x"e"^x(d/dx(x) + d/dx("e"^x)))/(x + "e"^x)^2`

= `((x + "e"^x)[x"e"^x + "e"^x(1)] - x"e"^x(1 + "e"^x))/(x + "e"^x)^2`

=`((x + "e"^x)(x"e"^x + "e"^x) - x"e"^x(1 + "e"^x))/(x + "e"^x)^2`

= `((x + "e"^x)"e"^x(x + 1) - x"e"^x(1 + "e"^x))/(x + "e"^x)^2`

= `("e"^x[(x + "e"^x)(x + 1) - x(1 + "e"^x)])/(x + "e"^x)^2`

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Rules of Differentiation (Without Proof)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Differentiation - Exercise 9.1 [पृष्ठ १२०]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
पाठ 9 Differentiation
Exercise 9.1 | Q IV. (5) | पृष्ठ १२०

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