मराठी

Differentiate the following function w.r.t.x. : 2xlogx

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प्रश्न

Differentiate the following function w.r.t.x. : `2^x/logx`

बेरीज
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उत्तर

Let y = `2^x/logx`

Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx" (2^x/logx)`

=` (log x  d/dx (2^x) - 2^x  d/dx (logx))/(logx)^2`

= `(log x. 2^x . log 2 - 2^x . 1/x)/(log x)^2`

= `[2^x (log x log 2 - 1/x)]/(log x)^2`

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Rules of Differentiation (Without Proof)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Differentiation - Exercise 9.2 [पृष्ठ १२२]

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बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 9 Differentiation
Exercise 9.2 | Q I. (6) | पृष्ठ १२२

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