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प्रश्न
Differentiate the following function w.r.t.x : `(x^2 + 1)/x`
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उत्तर
Let y = `(x^2 + 1)/x`
Differentiating w.r.t. x, we get
`dy/dx= d/dx((x^2 + 1)/x)`
= `(xd/dx(x^2 + 1) - (x^2 + 1)d/dx(x))/x^2`
= `(x(2x + 0) - (x^2 + 1)(1))/x^2`
= `(2x^2 - x^2 - 1)/x^2`
`dy/dx=(x^2 - 1)/x^2`
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