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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the combined equation of the following pair of lines: Passing through (2, 3) and perpendicular to the lines 3x + 2y – 1 = 0 and x – 3y + 2 = 0.

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प्रश्न

Find the combined equation of the following pair of lines:

Passing through (2, 3) and perpendicular to the lines 3x + 2y – 1 = 0 and x – 3y + 2 = 0.

बेरीज
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उत्तर

Let L1 and L2 be the lines passing through the point (2, 3) and perpendicular to the lines 3x + 2y – 1 = 0 and x – 3y + 2 = 0 respectively.

Slopes of the lines 3x + 2y – 1 = 0 and x – 3y + 2 = 0 are `(-3)/2` and `(-1)/-3 = 1/3` respectively.

∴ Slopes of the lines L1 and L2 are `2/3` and –3 respectively.

Since the lines L1 and L2 pass through the point (2, 3), their equations are

y – 3 = `2/3("x" - 2)` and y – 3 = –3(x – 2)

∴ 3y – 9 = 2x – 4 and y – 3 = –3x + 6 

∴ 2x – 3y + 5 = 0 and 3x + y – 9 = 0

∴ Their combined equation is (2x – 3y + 5)(3x + y – 9) = 0

∴ 6x2 + 2xy – 18x – 9xy – 3y2 + 27y + 15x + 5y – 45 = 0

∴ 6x2 – 7xy – 3y2 – 3x + 32y – 45 = 0

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पाठ 4: Pair of Straight Lines - Exercise 4.1 [पृष्ठ ११९]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 4 Pair of Straight Lines
Exercise 4.1 | Q 1.4 | पृष्ठ ११९

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