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प्रश्न
Find the area of triangle PQR formed by the points P(–5, 7), Q(–4, –5) and R(4, 5).
बेरीज
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उत्तर
Here x1 = –5, x2 = –4, x3 = 4 and y1 = 7, y2 = –5, y3 = 5
∴ Area of ΔPQR = `1/2 [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]`
= `1/2 [-5(-5 - 5) -4(5 - 7) + 4(7 + 5)]`
= `1/2 [-5(-10) - 4(-2) + 4(12)]`
= `1/2 [50 + 8 + 48]`
= `1/2 xx 106`
= 53 sq. units
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