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प्रश्न
Find the area of the triangle whose vertices are (0, 0), (1, 2) and (4, 3)
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उत्तर
The given points are (0, 0), (1, 2) and (4, 3)
Area of the triangle with vertices
(x1, y1), (x2, y2) and (x3, y3) is
Δ = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`
∴ The area of the triangle with vertices (0, 0), (1, 2) and (4, 3) is
Δ = `1/2|(0, 0, 1),(1, 2, 1),(4, 3, 1)|`
Δ = `1/2[1(3 - 8)]`
= `1/2 xx -5`
= `(-5)/2`
Area cannot be negative.
Taking positive value, we have required area Δ = `5/2` sq.units
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