Question

Find the area of the triangle whose vertices are (0, 0), (1, 2) and (4, 3)

Answer 1

The given points are (0, 0), (1, 2) and (4, 3)

Area of the triangle with vertices

(x₁, y₁), (x₂, y₂) and (x₃, y₃) is

Δ = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`

∴ The area of the triangle with vertices (0, 0), (1, 2) and (4, 3) is

Δ = `1/2|(0, 0, 1),(1, 2, 1),(4, 3, 1)|`

Δ = `1/2[1(3 - 8)]`

= `1/2 xx -5`

= `(-5)/2`

Area cannot be negative.

Taking positive value, we have required area Δ = `5/2` sq.units