Advertisements
Advertisements
प्रश्न
Find the area of region bounded by the line x = 2 and the parabola y2 = 8x
Advertisements
उत्तर

Here, y2 = 8x and x = 2
y2 = 8(2) = 16
∴ y = ±4
Required area = `2 int_0^2 sqrt(8x) "d"x`
= `2 xx 2sqrt(2) int_0^2 sqrt(x) "d"x`
= `4sqrt(2) xx 2/3 [x^(3/2)]_0^2`
= `(8sqrt(2))/3 [(2)^(3/2)]`
= `(8sqrt(2))/3 xx 2sqrt(2)`
= `32/3` sq.units
Hence, the area of the region = `32/3` sq.units
APPEARS IN
संबंधित प्रश्न
Using the method of integration, find the area of the triangular region whose vertices are (2, -2), (4, 3) and (1, 2).
Find the area of the region bounded by the curve x2 = 16y, lines y = 2, y = 6 and Y-axis lying in the first quadrant.
The area bounded by the curve y = x | x|, x-axis and the ordinates x = –1 and x = 1 is given by ______.
[Hint: y = x2 if x > 0 and y = –x2 if x < 0]
Find the area of ellipse `x^2/1 + y^2/4 = 1`
Sketch the graph of y = \[\sqrt{x + 1}\] in [0, 4] and determine the area of the region enclosed by the curve, the x-axis and the lines x = 0, x = 4.
Using integration, find the area of the region bounded by the line 2y = 5x + 7, x-axis and the lines x = 2 and x = 8.
Sketch the graph y = |x + 1|. Evaluate\[\int\limits_{- 4}^2 \left| x + 1 \right| dx\]. What does the value of this integral represent on the graph?
Find the area of the region bounded by the curve \[x = a t^2 , y = 2\text{ at }\]between the ordinates corresponding t = 1 and t = 2.
Using integration, find the area of the region bounded by the triangle ABC whose vertices A, B, C are (−1, 1), (0, 5) and (3, 2) respectively.
Find the area of the region {(x, y) : y2 ≤ 8x, x2 + y2 ≤ 9}.
Draw a rough sketch of the region {(x, y) : y2 ≤ 3x, 3x2 + 3y2 ≤ 16} and find the area enclosed by the region using method of integration.
Prove that the area in the first quadrant enclosed by the x-axis, the line x = \[\sqrt{3}y\] and the circle x2 + y2 = 4 is π/3.
Find the area of the region bounded by \[y = \sqrt{x}, x = 2y + 3\] in the first quadrant and x-axis.
Find the area of the region enclosed by the parabola x2 = y and the line y = x + 2.
Using integration find the area of the region bounded by the curves \[y = \sqrt{4 - x^2}, x^2 + y^2 - 4x = 0\] and the x-axis.
Find the area enclosed by the curves 3x2 + 5y = 32 and y = | x − 2 |.
The area bounded by the parabola x = 4 − y2 and y-axis, in square units, is ____________ .
If An be the area bounded by the curve y = (tan x)n and the lines x = 0, y = 0 and x = π/4, then for x > 2
The area bounded by the curve y = x4 − 2x3 + x2 + 3 with x-axis and ordinates corresponding to the minima of y is _________ .
The area of the region \[\left\{ \left( x, y \right) : x^2 + y^2 \leq 1 \leq x + y \right\}\] is __________ .
The area of the region bounded by the parabola y = x2 + 1 and the straight line x + y = 3 is given by
The area of the region (in square units) bounded by the curve x2 = 4y, line x = 2 and x-axis is
Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices area A(1, 2), B (2, 0) and C (4, 3).
Find the area of the region bounded by the curve ay2 = x3, the y-axis and the lines y = a and y = 2a.
The area of the region bounded by the curve y = x2 and the line y = 16 ______.
The area of the region bounded by the curve y = x2 + x, x-axis and the line x = 2 and x = 5 is equal to ______.
Find the area of the region bounded by the curve y2 = 4x, x2 = 4y.
Find the area of region bounded by the triangle whose vertices are (–1, 1), (0, 5) and (3, 2), using integration.
Compute the area bounded by the lines x + 2y = 2, y – x = 1 and 2x + y = 7.
Find the area bounded by the lines y = 4x + 5, y = 5 – x and 4y = x + 5.
The area of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is ______.
Find the area of the region bounded by the curve `y^2 - x` and the line `x` = 1, `x` = 4 and the `x`-axis.
What is the area of the region bounded by the curve `y^2 = 4x` and the line `x` = 3.
Smaller area bounded by the circle `x^2 + y^2 = 4` and the line `x + y = 2` is.
The area bounded by the curve `y = x^3`, the `x`-axis and ordinates `x` = – 2 and `x` = 1
The area of the region S = {(x, y): 3x2 ≤ 4y ≤ 6x + 24} is ______.
Let a and b respectively be the points of local maximum and local minimum of the function f(x) = 2x3 – 3x2 – 12x. If A is the total area of the region bounded by y = f(x), the x-axis and the lines x = a and x = b, then 4A is equal to ______.
Find the area of the following region using integration ((x, y) : y2 ≤ 2x and y ≥ x – 4).
Using integration, find the area bounded by the curve y2 = 4ax and the line x = a.
Evaluate:
`int_0^1x^2dx`
