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Find Points at Which the Tangent to the Curve Y = X3 − 3x2 − 9x + 7 is Parallel to the X-axis. - Mathematics

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प्रश्न

Find points at which the tangent to the curve y = x3 − 3x2 − 9x + 7 is parallel to the x-axis.

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उत्तर

When x = 3, y = (3)3 − 3 (3)2 − 9 (3) + 7 = 27 − 27 − 27 + 7 = −20.

When x = −1, y = (−1)3 − 3 (−1)2 − 9 (−1) + 7 = −1 − 3 + 9 + 7 = 12.

Hence, the points at which the tangent is parallel to the x-axis are (3, −20) and

(−1, 12).

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पाठ 6: Application of Derivatives - Exercise 6.3 [पृष्ठ २११]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 6 Application of Derivatives
Exercise 6.3 | Q 7 | पृष्ठ २११

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