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Find the Points of Discontinuity, If Any, of the Following Functions: F ( X ) = { E X − 1 Log E ( 1 + 2 X ) , If X ≠ 0 7 , If X = 0 - Mathematics

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प्रश्न

Find the points of discontinuity, if any, of the following functions: 

\[f\left( x \right) = \begin{cases}\frac{e^x - 1}{\log_e (1 + 2x)}, & \text{ if }x \neq 0 \\ 7 , & \text{ if } x = 0\end{cases}\]
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उत्तर

Given: 

\[f\left( x \right) = \begin{cases}\frac{e^x - 1}{\log_e (1 + 2x)}, & \text{ if }x \neq 0 \\ 7 , & \text{ if } x = 0\end{cases}\]

We have 

\[\lim_{x \to 0} f\left( x \right) = \lim_{x \to 0} \frac{e^x - 1}{\log_e \left( 1 + 2x \right)} = \lim_{x \to 0} \frac{\left( \frac{e^x - 1}{x} \right)}{\left( \frac{2 \log_e \left( 1 + 2x \right)}{2x} \right)} = \frac{1}{2} \times \frac{\lim_{x \to 0} \left( \frac{e^x - 1}{x} \right)}{\lim_{x \to 0} \left( \frac{\log_e \left( 1 + 2x \right)}{2x} \right)} = \frac{1}{2}\]

It is given that 

\[f\left( 0 \right) = 7\]
⇒  \[\lim_{x \to 0} f\left( x \right) \neq f\left( 0 \right)\]

Hence, the given function is discontinuous at x = 0 and continuous elsewhere.

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पाठ 9: Continuity - Exercise 9.2 [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 9 Continuity
Exercise 9.2 | Q 3.07 | पृष्ठ ३४

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