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Find out the increase in moment of inertia I of a uniform rod (coefficient of linear expansion α) about its perpendicular bisector when its temperature is slightly increased by ∆T.

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प्रश्न

Find out the increase in moment of inertia I of a uniform rod (coefficient of linear expansion α) about its perpendicular bisector when its temperature is slightly increased by ∆T.

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उत्तर

Let the mass and length of a uniform rod be M and l respectively.

Moment of inertia of the rod about its perpendicular bisector. `(i) = (Ml^2)/12`

The increase in length of the rod when temperature is increased by ∆T is given by `∆l = l.α∆T`  .....(i)

∴ New moment of inertia of the rod `(I) = M/12 (l + ∆l)^2`

= `M/12 (l^2 + ∆l^2 + 2I∆l)`

As the change in length ∆l is very small, therefore, neglecting `(∆l)^2`, we get

`I^' = M/12 (l^2 + 2l∆l)`

= `(Ml^2)/12 + (MI∆l)/6`

= `l + (MI∆l)/6`

∴ Increase in the moment of inertia `∆I = l - I`

= `(MI∆l)/6`

= `2 xx ((Ml^2)/12) (∆l)/l`

`∆I = 2*I α∆T`  ......[Using equation (i)]

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पाठ 11: Thermal Properties of Matter - Exercises [पृष्ठ ८१]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 11 Thermal Properties of Matter
Exercises | Q 11.18 | पृष्ठ ८१

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