मराठी

Find the Number of Metallic Circular Discs with 1.5 Cm Base Diameter and of Height 0.2 Cm to Be Melted to Form a Right Circular Cylinder of Height 10 Cm and Diameter 4.5 Cm .

Advertisements
Advertisements

प्रश्न

Find the number of metallic circular discs with a 1.5 cm base diameter and of height  0.2 cm to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

बेरीज
Advertisements

उत्तर

Given the diameter of the base of the the circular disc = 1.5 cm

Height = 0.2 cm

Volume of the circular disc =  \[\pi r^2 h = \pi\times\left( \frac{1 . 5}{2} \right)^2 \times 0 . 2 = \pi \times \left( 0 . 75 \right)^2 \times 0 . 2\]       ...(i)

Height of the cylinder = 10 cm

Diameter = 4.5 cm

Volume of the cylinder = 

\[\pi R^2 H = \pi \left( \frac{4 . 5}{2} \right)^2 \times 10 = \pi \times \left( 2 . 25 \right)^2 \times 10 . . . \left( ii \right)\]

Now since the circular discs are used to make the cylinder so, let n be the number of circular discs required.

\[n \times \text{ Volume of circular disc = Volume of cylinder}\]

\[\Rightarrow \frac{\text { Volume of cylinder } }{\text{ Volume of circular disc}} = n\]

\[\Rightarrow \frac{\pi \times \left( 2 . 25 \right)^2 \times 10}{\pi \times \left( 0 . 75 \right)^2 \times 0 . 2} = n\]

\[\Rightarrow n = 450\]

Hence, 450 metallic circular discs need to be melted to form the right circular cylinder.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Surface Areas and Volumes - Exercise 14.1 [पृष्ठ २८]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 10
पाठ 14 Surface Areas and Volumes
Exercise 14.1 | Q 9 | पृष्ठ २८

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, ∠ DAB = 900, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. [Take π=22/7]

 


150 spherical marbles, each of diameter 1.4 cm, are dropped in a cylindrical vessel of diameter 7 cm containing some water, which are completely immersed in  water. Find the rise in the level of water in the vessel.


The number of solid spheres, each of diameter 6 cm that can be made by melting a solid metal cylinder of height 45 cm and diameter 4 cm, is:


In Fig. 4, from the top of a solid cone of height 12 cm and base radius 6 cm, a cone of height 4 cm is removed by a plane parallel to the base. Find the total surface area of the remaining solid. (Use `pi=22/7` and `sqrt5=2.236`)


A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy [Use π =`22/7`]


Water in a canal, 5·4 m wide and 1·8 m deep, is flowing with a speed of 25 km/hour. How much area can it irrigate in 40 minutes, if 10 cm of standing water is required for irrigation?


The diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm respectively. If its height is 24 cm, find:

1) The area of the metal sheet used to make the bucket.

2) Why we should avoid the bucket made by ordinary plastic? [Use π = 3.14]


A toy is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The radius and height of the cylindrical part are 5 cm and 13 cm respectively.The radii of the hemispherical and conical parts are the same as that of the cylindrical part.Find the surface area of the toy if the total height of the toy is 30 cm.


A bucket made of aluminum sheet is of height 20cm and its upper and lower ends are of radius 25cm an 10cm, find cost of making bucket if the aluminum sheet costs Rs 70 per
100 cm2


A metallic cylinder has radius 3 cm and height 5 cm. To reduce its weight, a conical hole is drilled in the cylinder. The conical hole has a radius of `3/2` cm and its depth is `8/9 `cm. Calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shape.


A solid metallic sphere of diameter 28 cm is melted and recast into a number of smaller cones, each of diameter  4 \[\frac{2}{3}\] cm and height 3 cm. Find the number of cones so formed.


A solid is in the form of a cylinder with hemispherical ends. Total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid.


From a solid cube of side 7 cm , a conical cavity of height 7 cm and radius 3 cm is hollowed out . Find the volume of the remaining solid.


A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have? Find the cost of painting the total surface area of the solid so formed, at the rate of ₹5 per 100 sq cm. [Use ππ = 3.14]


Five identical cubes, each of edge 5 cm, are placed adjacent to each other. Find the volume of the resulting cuboid.


The volume of a hemisphere is 19404 cm3. The total surface area of the hemisphere is


A container opened at the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container, at the rate of ₹ 50 per litre. Also find the cost of metal sheet used to make the container, if it costs ₹ 10 per 100 cm2. (Take π = 3⋅14)


The shape of a gilli, in the gilli-danda game (see figure), is a combination of ______.


A tent is in the shape of a cylinder surmounted by a conical top. If the height and radius of the cylindrical part are 3 m and 14 m respectively, and the total height of the tent is 13.5 m, find the area of the canvas required for making the tent, keeping a provision of 26 m2 of canvas for stitching and wastage. Also, find the cost of the canvas to be purchased at the rate of ₹ 500 per m2.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×