Question

Find the intercepts cut off by the plane 2x + y – z = 5.

Find the sum of the intercepts cut off by the plane \[2x + y - z = 5,\]on the coordinate axes.

 

Answer 1

2x + y – z = 5  ...(1)

Dividing both sides of equation (1) by 5, we obtain

Thus, the intercepts cut off by the plane are `5/2, 5 and -5`

∴ Required sum of intercepts = \[\frac{5}{2} + 5 + \left( - 5 \right) = \frac{5}{2}\] .