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Find D Y D X in the Following Case ( X + Y ) 2 = 2 a X Y ? - Mathematics

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प्रश्न

Find  \[\frac{dy}{dx}\] in the following case \[\left( x + y \right)^2 = 2axy\] ?

 

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उत्तर

\[\text{ We have, } \left( x + y \right)^2 = 2axy\]

Differentiating with respect to x, we get,

\[\Rightarrow \frac{d}{dx} \left( x + y \right)^2 = \frac{d}{dx}\left( 2axy \right)\]
\[ \Rightarrow 2\left( x + y \right)\frac{d}{dx}\left( x + y \right) = 2a\left[ x\frac{d y}{d x} + y\frac{d}{dx}\left( x \right) \right] \]
\[ \Rightarrow 2\left( x + y \right)\left[ 1 + \frac{d y}{d x} \right] = 2a\left[ x\frac{d y}{d x} + y\left( 1 \right) \right]\]
\[ \Rightarrow 2\left( x + y \right) + 2\left( x + y \right)\frac{d y}{d x} = 2ax\frac{d y}{d x} + 2ay\]
\[ \Rightarrow \frac{d y}{d x}\left[ 2\left( x + y \right) - 2ax \right] = 2ay - 2\left( x + y \right)\]
\[ \Rightarrow \frac{d y}{d x} = \frac{2\left[ ay - x - y \right]}{2\left[ x + y - ax \right]}\]
\[ \Rightarrow \frac{d y}{d x} = \left( \frac{ay - x - y}{x + y - ax} \right)\]

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पाठ 11: Differentiation - Exercise 11.04 [पृष्ठ ७४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.04 | Q 7 | पृष्ठ ७४

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