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Find the Binding Energy per Nucleon of 197 79 Au If Its Atomic Mass is 196.96 U. - Physics

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प्रश्न

Find the binding energy per nucleon of `""_79^197"Au"` if its atomic mass is 196.96 u.

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)

बेरीज
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उत्तर

Given:-

Atomic mass of Au, A = 196.96
Atomic number of Au, Z = 79
Number of neutrons, N = 118
Binding energy,

`B = (Zm_p + Nm_n - M)c^2`

Here, mp = Mass of proton
M = Mass of nucleus
mn = Mass of neutron
c = Speed of light

On substituting the respective values, we get

`B = [(79 xx 1.007276 + 118 xx 1.008665) "u" - 196.96  "u" ] c^2`

`= (198.597274 - 196.96) xx 931  "MeV"`

`= 1524.302094  "MeV"`

Binding energy per nucleon = `1524.3/197 = 7.737  "MeV"`

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पाठ 24: The Nucleus - Exercises [पृष्ठ ४४२]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 24 The Nucleus
Exercises | Q 5 | पृष्ठ ४४२

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