Advertisements
Advertisements
प्रश्न
Find A as required:
The least number 567A is divisible by 3
Advertisements
उत्तर
A number is divisible by 3 if the sum of its digits is divisible by 3
Sum of digits of 567A = 5 + 6 + 7 + A
= 18 + A
∴ 18 is divisible by 3
∴ A maybe 0
The number will be 5670
APPEARS IN
संबंधित प्रश्न
If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
If x is a digit such that the number \[\overline{{18x71}}\] is divisible by 3, find possible values of x.
Given that the number \[\overline{{67y19}}\] is divisible by 9, where y is a digit, what are the possible values of y?
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
7×34 divisible by 9?
Check the divisibility of 2146587 by 3.
The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is __________
Let abc be a three-digit number. Then abc – cba is not divisible by ______.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
Why is 872 NOT divisible by 3?
